Who wants to help me with a math problem?
I need to know how many unique combinations of three numbers I can get on a clock face (using just the hours, not all the minutes).
So very example: 12-1-2, 12-1-3, 12-1-4....1-2-5, 1-2-6 et al.
What's the formula for that and what's my total, por favor!
Dang. That is getting to be a long time.
Does order matter, Hec? Is 1-2-3 the same or different from 2-3-1?
ETA If it does, the formula will be 12!/9! or 12*11*10
If it doesn't. 12!/(3!*9!) or 12*11*10/(3*2)
Does order matter, Hec? Is 1-2-3 the same or different from 2-3-1?
That is a good question. 1-2-3 is the same as 2-3-1 in this example.
So this one?
If it doesn't. 12!/(3!*9!) or 12*11*10/(3*2)
V-dub, it's been so long since you were here that your tagline is MARRIED!!! Seems like you might want to update it. :-)
About 19 years ago I was on a panel at Lunacon talking about current SF/F on TV, and about the time we were wrapping up, I remembered to mention that a TV series of
Buffy The Vampire Slayer
would be starting up soon, that while the movie had been uneven, the adaptation was produced by the original writer, so we could hope.
(Almost the best prediction I ever made -- the best was the first time I saw some kids playing a game of Magic The Gathering, and when they explained how it worked, I said, "The creators are going to make a million bucks!")
-t!!!!
Good point, Connie. I'll have to fix that.
yeah 19 years is long ago.
I just checked my delurking date, this Monday was my 15th year here. WHAT THE HELL?!?!